# How do you factor 2x^3-14x^2-16x?

Mar 10, 2018

$2 {x}^{3} - 14 {x}^{2} - 16 x = 2 x \left(x - 8\right) \left(x + 1\right)$

#### Explanation:

The common factor is $2 x :$

$2 {x}^{3} - 14 {x}^{2} - 16 x = 2 x \left({x}^{2} - 7 x - 8\right)$

Look for two numbers that add to -7 and multiply to -8: -8 and +1

$2 x \left({x}^{2} - 7 x - 8\right) = 2 x \left(x - 8\right) \left(x + 1\right)$