# How do you factor -2x^3 + 16x ?

Jul 5, 2017

$- 2 x \left({x}^{2} - 8\right)$ or $- 2 x \left(x - \sqrt{8}\right) \left(x + \sqrt{8}\right)$
First take out the -2, so it'll become $- 2 \left({x}^{3} - 8 x\right)$
Then notice that you can take out an x from both terms, so it'll simplify to $- 2 x \left({x}^{2} - 8\right)$.
This can be further simplified down to $- 2 x \left(x - \sqrt{8}\right) \left(x + \sqrt{8}\right)$