How do you factor $-2x^3 + 16x$ ?

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Answer 1 · 2017-07-05T14:23:50

$-2x(x^2-8)$ or $-2x(x-sqrt(8))(x+sqrt(8))$

First take out the -2, so it'll become $-2(x^3-8x)$

Then notice that you can take out an x from both terms, so it'll simplify to $-2x(x^2-8)$ .

This can be further simplified down to $-2x(x-sqrt(8))(x+sqrt(8))$

How do you factor -2x^3 + 16x -2x^3 + 16x ?