# How do you factor 2x^3 + 3x^2 - 8x-12?

Jun 29, 2016

$\left(x - 2\right) \left(2 {x}^{2} + 7 x + 6\right)$

#### Explanation:

$y = 2 {x}^{3} + 3 {x}^{2} - 8 x - 12$.
Note that f(2) = 0, then, one factor is (x - 2).
After division, we get:
$y = \left(x - 2\right) \left(2 {x}^{3} + 7 x + 6\right)$
The trinomial in parentheses can't be factored because its D < 0.
Therefor,
$y = \left(x - 2\right) \left(2 {x}^{3} + 7 x + 6\right)$