How do you factor #2xy+8x+6y+24 #? Algebra Polynomials and Factoring Factoring Completely 1 Answer EZ as pi May 25, 2018 #2(y+4)(x+3)# Explanation: Group the four terms into two groups. #(2xy+8x)+(6y+24)# #=2x(y+4) +6(y+4)" "larr# take out a common factor #=(y+4)(2x+6)" "larr# take out the common bracket #=2(y+4)(x+3)" "larr# take out the common factor Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 1514 views around the world You can reuse this answer Creative Commons License