# How do you factor 2y^4 + 3y^3 - 9y^2?

May 8, 2015

You can factor $2 {y}^{4} + 3 {y}^{3} - 9 {y}^{2}$ by grouping out ${y}^{2}$.
The ${y}^{2}$ is present in all terms, so you can pull it out like so:

${y}^{2} \left(2 {y}^{2} + 3 y - 9\right)$

May 8, 2015

$2 {y}^{4} + 3 {y}^{3} - 9 {y}^{2}$

Extract the obvious common factor from each term
${y}^{2} \left(2 {y}^{2} + 3 y - 9\right)$

$y \left(2 y - 3\right) \left(y + 3\right)$