Question

How do you factor `2y^4 + 3y^3 - 9y^2`?

Answer 1

You can factor `2y^4 + 3y^3 - 9y^2` by grouping out `y^2`.
The `y^2` is present in all terms, so you can pull it out like so:

`y^2(2y^2+3y-9)`

Answer 2

`2y^4+3y^3-9y^2`

Extract the obvious common factor from each term
`y^2(2y^2+3y-9)`

Then factor the quadratic
`y(2y-3)(y+3)`