How do you factor #316 - 343t^3#? Algebra Polynomials and Factoring Factor Polynomials Using Special Products 1 Answer sankarankalyanam Oct 5, 2017 #(6-7t)(36+42t+t^2)# Explanation: Assuming the question as #216-343t^3# as suggested by Mr George, #a^3-b^3=(a-b)(a^2+ab+b^2# #6^3=216# Hence #a=6 # & # 7^3=343 # and hence #b=7#. The factors are #(6-7t)(6^2+(6*7t)+(7t)^2)# #(6-7t)(36+42t+t^2)# Answer link Related questions How do you factor special products of polynomials? How do you identify special products when factoring? How do you factor #x^3 -8#? What are the factors of #x^3y^6 – 64#? How do you know if #x^2 + 10x + 25# is a perfect square? How do you write #16x^2 – 48x + 36# as a perfect square trinomial? What is the difference of two squares method of factoring? How do you factor #16x^2-36# using the difference of squares? How do you factor #2x^4y^2-32#? How do you factor #x^2 - 27#? See all questions in Factor Polynomials Using Special Products Impact of this question 1200 views around the world You can reuse this answer Creative Commons License