# How do you factor 35a^3bc^2-45a^2b^2c?

$5 {a}^{2} b c \left(7 a c - 9 b\right) = 0$
$35 {a}^{3} b {c}^{2} - 45 {a}^{2} {b}^{2} c = 0$
$5 {a}^{2} b c \left(7 a c - 9 b\right) = 0$