How do you factor #35a^3bc^2-45a^2b^2c#? Algebra Polynomials and Factoring Factoring Completely 1 Answer AAA Nov 14, 2015 #5a^2bc(7ac-9b)=0# Explanation: #35a^3bc^2-45a^2b^2c=0# Factor out #5a^2bc(7ac-9b)=0# Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 2619 views around the world You can reuse this answer Creative Commons License