How do you factor $36t^4 + 29t^2 - 7$ ?

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Answer 1 · 2016-06-27T02:54:29

$(36t^2-7)(t^2+1)$

Let $t^2$ = x. Now the given equation becomes as a quadratic equation and you can factorize this easily.

$36x^2 + 29x - 7$

$36x^2 + 36x - 7x - 7$

$36x(x+1) - 7(x+1)$

$(36x-7)(x+1)$

Substituting x, we get $(36t^2-7)(t^2+1)$

How do you factor 36t^4 + 29t^2 - 7 36t^4 + 29t^2 - 7 ?