# How do you factor 36t^4 + 29t^2 - 7 ?

Jun 27, 2016

$\left(36 {t}^{2} - 7\right) \left({t}^{2} + 1\right)$

#### Explanation:

Let ${t}^{2}$ = x. Now the given equation becomes as a quadratic equation and you can factorize this easily.

$36 {x}^{2} + 29 x - 7$

$36 {x}^{2} + 36 x - 7 x - 7$

$36 x \left(x + 1\right) - 7 \left(x + 1\right)$

$\left(36 x - 7\right) \left(x + 1\right)$

Substituting x, we get $\left(36 {t}^{2} - 7\right) \left({t}^{2} + 1\right)$