How do you factor $36 y^{2} - 16$ $36y^2-16$ ?

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Answer 1 · 2015-06-01T23:29:44

$36 y^{2} - 16 = {(6 y)}^{2} - 4^{2} = (6 y - 4) (6 y + 4)$ $36y^2-16=(6y)^2-4^2=(6y-4)(6y+4)$

...using the difference of square identity:

$a^{2} - b^{2} = (a - b) (a + b)$ $a^2-b^2 = (a-b)(a+b)$

How do you factor 36y2−1636y^2-16?