How do you factor #3a^2 + 14a − 24#?
We know there must be a
You then use trial and error to find a the other numbers which multiply together to make
(3a - 4)(a + 6)
Use the systematic, non-guessing new AC Method (Socratic Search).
p' and q' have opposite signs because ac < 0.
Factor pairs of (ac = -72) --> (-3,24) (-4, 18). This sum is 14 = b. Then,
p' = -4 and q' = 18.
Back to trinomial y,