How do you factor #3a(x-y) + 2b(y^2-x^2)#? Algebra Polynomials and Factoring Factoring Completely 1 Answer Konstantinos Michailidis May 23, 2016 Rewrite this #3a(x-y) + 2b(y^2-x^2)=3a(x-y)-2b(x^2-y^2)= 3a(x-y)-2b(x-y)(x+y)= (x-y)*[3a-2b(x+y)]# Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 1202 views around the world You can reuse this answer Creative Commons License