How do you factor $-3ax^2p + 24pa + 6axp$ ?

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Answer 1 · 2016-09-19T09:38:05

$-3ap(x-4)(x+2)$

Always look for a common factor first, then look again.

$-3ax^2p + 24pa + 6axp$

It is better to have the negative sign at the front rather than a $-x^2$ term inside the bracket.

= $-3ap(x^2 -8-2x)" "larr$ re-arrange the terms

= $-3ap(x^2 -2x -8)" "larr$ find factors of 8 which differ by 2

= $-3ap(x-4)(x+2)$

How do you factor -3ax^2p + 24pa + 6axp-3ax^2p + 24pa + 6axp?