# How do you factor 3cd – 6cy + 2xd – 4xy?

Mar 23, 2016

$\left(d - 2 y\right) \left(3 c + 2 x\right)$

#### Explanation:

It is a matter of spotting the grouping and perhaps a bit of experimenting

$3 c \left(d - 2 y\right) + 2 x \left(d - 2 y\right) \text{ }$ I struck lucky first time

The common factor is $\left(d - 2 y\right)$ so we have

$\left(d - 2 y\right) \left(3 c + 2 x\right)$

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Check:$\text{ "(d-2y)(3c+2x) =3dc+2xd-6yc-4yx" }$ It matches so ok!