Question

How do you factor `3cd – 6cy + 2xd – 4xy`?

Answer 1

`(d-2y)(3c+2x)`

Explanation:

It is a matter of spotting the grouping and perhaps a bit of experimenting

`3c(d-2y)+2x(d-2y)" "` I struck lucky first time

The common factor is `(d-2y)` so we have

`(d-2y)(3c+2x)`

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Check:`" "(d-2y)(3c+2x) =3dc+2xd-6yc-4yx" "` It matches so ok!