How do you factor #3m^4+243#? Algebra Polynomials and Factoring Factor Polynomials Using Special Products 1 Answer Azimet Jan 18, 2017 Answer: #3(m^4 + 81)# Explanation: No #m# can be factored out of both terms, since #m# isn't a factor of #243# (it's a variable). So, since #243# is divisible by #3#, we can factor a #3# out of the entire equation, put the rest in parentheses, and divide each term with #3# as such: #3(m^4 + 81)# Related questions How do you factor special products of polynomials? How do you identify special products when factoring? How do you factor #x^3 -8#? What are the factors of #x^3y^6 – 64#? How do you know if #x^2 + 10x + 25# is a perfect square? How do you write #16x^2 – 48x + 36# as a perfect square trinomial? What is the difference of two squares method of factoring? How do you factor #16x^2-36# using the difference of squares? How do you factor #2x^4y^2-32#? How do you factor #x^2 - 27#? See all questions in Factor Polynomials Using Special Products Impact of this question 282 views around the world You can reuse this answer Creative Commons License