Question

How do you factor `3n^2+2n-1`?

Answer 1

`3n^2+2n-1 = (3n-1)(n+1)`

I found this by recognising that if the original quadratic has factors with integer coefficients then they must be of the form `(3n+-1)` or `(n+-1)` in order that the leading and trailing coefficients be `3` and `-1`.