How do you factor #3t^2+14t-5#?

1 Answer
Jun 11, 2015

Answer:

Factor f(t) = 3t^2 + 14t - 5

Explanation:

I use the new AC Method (Google, Yahoo Search)
Convert f(t) to #f'(t) = t^2 + 14 t - 15.#
Factor pair of (a.c = -15)--> (-1, 15). This sum = 14 = b.
p' = -1 and q' = 15
#p = -1/3# and #q = 15/3 = 5#

Factored form f(t) = 3(t - 1/3)(t + 5) =# (3t - 1)(t + 5)#