# How do you factor 3x^2 - 10 + 3 = 0?

Mar 27, 2016

$y = 3 {x}^{2} - 10 + 3 =$ 3(x + p)(x + q)
Converted $y ' = {x}^{2} - 10 x + 9 =$ (x + p')(x + q').
Back to y --> $p = \frac{p '}{a} = - \frac{1}{3}$ and $q = \frac{q '}{a} = - \frac{9}{3} = - 3.$