How do you factor #3x^2 - 10x + 3?

$f \left(x\right) = 3 {x}^{2} - 10 x + 3 = \left(x - p\right) \left(x - q\right)$
Converted trinomial: $f ' \left(x\right) = {x}^{2} - 10 x + 9 = \left(x - p '\right) \left(x - q '\right)$with ac = 9
$p ' = - 1 \to p = \frac{p '}{a} = - \frac{1}{3}$
$q ' = - 9 \to q = \frac{q '}{a} = - \frac{9}{3} = - 3$