How do you factor #3x^2 - 12x - 4#?
Note that there are no "pretty" factors for this expression.
The best I could come up with is
The rational root theorem reveals no rational roots
so we can apply the quadratic formula to find zeros for this expression.
For a quadratic of the form
zeros occur at
Applying this to the given equation results in
Dividing the original expression by these factors leaves an additional factor of
So the complete factorization is
Use the improved quadratic formula (Socratic Search)
There are 2 real roots: