How do you factor #3x^2-13x+4#?
You can find its roots and then turn them into factors.
Using Bhaskara to find the roots:
Factoring your quadratic function, then:
There is another way. I use the new AC Method (Google, Yahoo Search) to factor trinomials
y = 3x^2 - 13x + 4 = (x - p)( - q)
Converted function: f'(x) = x^2 - 13x + 12.= (x - p')(x -q')
Compose factor pair of 12: (1, 12). This sum is 12 + 1 = 13 = -b.
Then p' = -1 and q' = -12.
Consequently, p = (p')/a = -1/3 and q' = (q')/a = -12/3 = -4
Factored form of y: y = (x - 1/3)(x - 4) = (3x - 1)(x - 4).