How do you factor # 3x^2 z – 3zx – 18z#?

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Answer 1 · 2018-04-25T18:40:44

#3z(x + 1)(x - 3)#

first, we can see that #3z# is a common factor in all three terms. isolate that out and factor the rest.

#3x^2z - 3zx - 18z#

#3z(x^2 - x - 6)#

#3z(x + 1)(x - 3)#

Answer 2 · 2018-04-25T18:50:47

#3z(x-3)(x+2)#

#"take out the "color(blue)"common factor "3z#

#=3z(x^2-x-6)#

#"the factors of - 6 which sum to - 1 are - 3 and + 2"#

#=3z(x-3)(x+2)#