Question

How do you factor `3x^3 + 3x² + x + 1`?

Answer 1

`(x + 1 )(3x^2 + 1 )`

Explanation:

Factor in 'groups'

# [ 3x^3 + 3x^2 ] + [ x + 1 ]

now factor each 'pair'

`3x^2 ( x + 1 ) + 1 (x+ 1 )`

common factor of (x + 1 )

hence (x + 1 )(`3x^2 + 1 )`