How do you factor $3x^3 + 9 x^2- 12x-36$ ?

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Answer 1 · 2017-09-29T16:55:24

$3(x+3)(x+2)(x-2).$

$3x^3+9x^2-12x-36,$

$=3{ul(x^3+3x^2)-ul(4x-12)},$

$=3{x^2(x+3)-4(x+3)},$

$=3(x+3){x^2-2^2},$

$=3(x+3)(x+2)(x-2).$

How do you factor 3x^3 + 9 x^2- 12x-363x^3 + 9 x^2- 12x-36?