How do you factor #3x^3+x^2-75x-25#?

1 Answer
Mar 29, 2017

This actually requires factoring by grouping. Let's group the function like this: #(3x^3+x^2)-(75x+25)#. We then factor the two groups to get #x^2(3x+1)-25(3x+1)#. The common factor between the two groups is #(3x+1)#, which we factor out to get #(3x+1)(x^2-25)#.

Now, we notice that #x^2-25=(x+5)(x-5)# (using the difference between squares identity).

Thus, our final answer is #(3x+1)(x+5)(x-5)#