How do you factor #3x^(6n) y^2 - 39x^(3n) y^2 +120y^2#?

1 Answer
Jun 5, 2016

Answer:

#3y^2(x^(3n) - 5)(x^(3n) - 8)#

Explanation:

Let 3y^2 be common factor -->
#f(x) = 3y^2(x^(6n) - 13x^(3n) + 40)#
Call #x^(3n) = X#. Factor the quadratic trinomial in X -->
#X^2 - 13X + 40. #
Find 2 numbers knowing sum (-13) and product (4).
They are -5 and -8.

#f(x) = 3y^2(X - 5)(X - 8) = 3y^2(x^(3n) - 5)(x^(3n) - 8)#