How do you factor $-3x(x-2)+4x(x+1)+9$ ?

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Answer 1 · 2016-06-24T15:39:09

$(x+1)(x+9)$

Multiply out the brackets

$-3x^2+6x" "+4x^2+4x" "+9$

$4x^4-3x^2+6x+4x+9$

$x^2+10x+9$

Notice that $1xx9=9" and that "1+9=10$

$(x+1)(x+9)$

How do you factor -3x(x-2)+4x(x+1)+9-3x(x-2)+4x(x+1)+9?