Question

How do you factor `3y^4-2y^2-5` completely?

Answer 1

`3 y^4 - 2 y^2 -5 = (y^2+1)(3 y^2 - 5)`

Explanation:

`3 y^4 - 2 y^2 -5`

`= 3 y^4 + 3 y^2 - 5 y^2-5`

`= 3 y^2(y^2+1) - 5( y^2+1)`

`= (y^2+1)(3 y^2 - 5)` [Ans]