How do you factor #3y-6x+4xy-2y^2 #, by grouping ?
1 Answer
May 6, 2018
Explanation:
#=color(red)(3)(y-2x)color(red)(-2y)(y-2x)larrcolor(blue)"by grouping"#
#"take out the "color(blue)"common factor "(y-2x)#
#=(y-2x)(color(red)(3-2y))#
#rArr3y-6x+4xy-2y^2=(y-2x)(3-2y)#
