How do you factor: [?]

y^2-6y+9 ?

Thanks.

1 Answer
Mar 9, 2018

Two ways to do it. See bellow

Explanation:

1st method.

Solve the equeation of second degree

y^2-6y+9=0. You will obtain 2 roots of this equation, lets say a_1 and a_2...so the factorization will be (y-a_1)(y-a_2)

Second Method. (A little bit more complicated dependeing of given equation. In this case it's easy)

Complete the square

y^2-6y+9=(y-3)^2=(y-3)(y-3)

Its obvious that prior values a_1 and a_2 are both equal to 3