How do you factor: [?]

#y^2-6y+9# ?

Thanks.

1 Answer
Mar 9, 2018

Answer:

Two ways to do it. See bellow

Explanation:

1st method.

Solve the equeation of second degree

#y^2-6y+9=0#. You will obtain 2 roots of this equation, lets say #a_1# and #a_2#...so the factorization will be #(y-a_1)(y-a_2)#

Second Method. (A little bit more complicated dependeing of given equation. In this case it's easy)

Complete the square

#y^2-6y+9=(y-3)^2=(y-3)(y-3)#

Its obvious that prior values #a_1# and #a_2# are both equal to 3