How do you factor #-4/3x+4/9=-x^2#?

1 Answer
Aug 15, 2017

Answer:

#x^2-4/3x+4/9=color(blue)((x-2/3)^2#

Refer to the explanation for the process.

Explanation:

Factor:

#-4/3x+4/9=-x^2#

Add #x^2# to both sides.

#x^2-4/3x+4/9=0#

Since the desired answer is the factors of the equation, the #0# will not be included in the expression.

Find two numbers that when added equal #-4/3# and when multiplied equal #4/9#. Both requirements are met by #-2/3#.

#x^2-4/3x+4/9=(x-2/3)(x-2/3)#

#x^2-4/3x+4/9=(x-2/3)^2#