How do you factor $-4/3x+4/9=-x^2$ ?

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Answer 1 · 2017-08-15T23:45:19

$x^2-4/3x+4/9=color(blue)((x-2/3)^2$

Refer to the explanation for the process.

Factor:

$-4/3x+4/9=-x^2$

Add $x^2$ to both sides.

$x^2-4/3x+4/9=0$

Since the desired answer is the factors of the equation, the $0$ will not be included in the expression.

Find two numbers that when added equal $-4/3$ and when multiplied equal $4/9$ . Both requirements are met by $-2/3$ .

$x^2-4/3x+4/9=(x-2/3)(x-2/3)$

$x^2-4/3x+4/9=(x-2/3)^2$

How do you factor -4/3x+4/9=-x^2-4/3x+4/9=-x^2?