How do you factor #4(x^2) - 28x + 49#? Algebra Polynomials and Factoring Factorization of Quadratic Expressions 1 Answer Nghi N Mar 29, 2018 #(2x - 7)^2# Explanation: It is a perfect square: #4x^2 - 28x + 49 = (2x - 7)^2# Answer link Related questions How do you factor trinomials? What is factorization of quadratic expressions? How do you factor quadratic equations with a coefficient? What are some examples of factoring quadratic expressions? How do you check that you factored a quadratic correctly? How do you factor #x^2+16x+48#? How do you factor #x^2-9x+20#? Question #3fdac How do you factor #8+z^6#? There is no GCF to be factor out, so is there another method to complete this? How do you factor #2t^2+7t+3#? See all questions in Factorization of Quadratic Expressions Impact of this question 1721 views around the world You can reuse this answer Creative Commons License