How do you factor #45x^2 - 60x +20 #?

1 Answer
radee
Nov 18, 2017

#5(3x - 2)^2#

Explanation:

#45x^2 - 60x + 20#

First factor out 5 so that you will be left with smaller coefficients
#5(9x^2 - 12x + 4)#

So we know that:

  • #9 = 3 * 3#
  • #4 = 2 * 2#
  • the format would be #(ax - b)(cx - d)# since the coefficient of #x# is negative and the constant is #+4#.

#5(9x^2 - 12x + 4)#
#5(3x - 2)(3x - 2)#
#5(3x - 2)^2#

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