How do you factor $49 w^{2} - 25$ $49w^2 -25$ ?

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Answer 1 · 2018-05-31T19:09:23

$(7 w + 5) (7 w - 5)$ $(7w + 5) (7w - 5)$

$49 w^{2} - 25$ $49w^2 - 25$

$7^{2} w^{2} - 5^{2}$ $7^2w^2 - 5^2$

Recall;

$a^{2} - b^{2} = (a + b) (a - b) \to difference of two squares..$ $a^2 - b^2 = (a + b) (a - b) -> "difference of two squares.."$

$7^{2} w^{2} - 5^{2} = (7 w + 5) (7 w - 5)$ $7^2w^2 - 5^2 = (7w + 5) (7w - 5)$

How do you factor 49w^2 -2549w2−2549w^2 -25?