How do you factor $49 x^{2} - 16$ $49x^2-16$ ?

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Answer 1 · 2015-05-24T03:33:47

$a^{2} - b^{2} = (a + b) (a - b)$ $color(blue)(a^2 - b^2 = (a+b)(a-b)$

$49 x^{2} - 16 = {(7 x)}^{2} - {(4)}^{2}$ $49x^2 - 16 = (7x)^2 - (4)^2$

${(7 x)}^{2} - {(4)}^{2} = (7 x - 4) (7 x + 4)$ $(7x)^2 - (4)^2 = color(red)((7x-4)(7x+4)$

How do you factor 49x2−1649x^2-16?