How do you factor $49 x^{2} - 81$ $49x^2 -81$ ?

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Answer 1 · 2018-03-22T05:26:39

$(7 x + 9) (7 x - 9)$ $(7x+9)(7x-9)$

Given -

$49 x^{2} - 81$ $49x^2-81$

It is in the form $a^{2} - b^{2}$ $a^2-b^2$

Factors for the expression $a^{2} - b^{2}$ $a^2-b^2$ is $(a + b) (a - b)$ $(a+b)(a-b)$

Following this, we can find the factors for the given expression $49 x^{2} - 81$ $49x^2-81$

$(7 x + 9) (7 x - 9)$ $(7x+9)(7x-9)$

How do you factor 49x2−8149x^2 -81 ?