# How do you factor 4a^3 b^4z^3 + 2a^2bz^4?

$4 {a}^{3} {b}^{4} {z}^{3} + 2 {a}^{2} b {z}^{4} = 2 {a}^{2} b {z}^{3} \left(2 a {b}^{3} + z\right)$
Both of the terms are divisible by $2 {a}^{2} b {z}^{3}$ so we can separate that out, but no further factorisation is possible.