# How do you factor 4c ^ { 2} - 9c ^ { 3}?

Mar 4, 2018

See a solution process below:

#### Explanation:

Rewrite each term as:

$\left(4 \times \textcolor{red}{{c}^{2}}\right) - \left(9 c \times \textcolor{red}{{c}^{2}}\right)$

Now, factor out the common term:

$\left(4 - 9 c\right) \textcolor{red}{{c}^{2}}$