# How do you factor 4c^2d^2-9cdx+5x^2?

$\left(4 c d - 5 x\right) \left(c d - x\right)$
$4 {c}^{2} {d}^{2} - 9 c \mathrm{dx} + 5 {x}^{2} = 4 {c}^{2} {d}^{2} - 4 c \mathrm{dx} - 5 c \mathrm{dx} + 5 {x}^{2} = 4 c d \left(c d - x\right) - 5 x \left(c d - x\right) = \left(4 c d - 5 x\right) \left(c d - x\right)$[Ans]