How do you factor $4m(4 - m) + 3n(4 - m)$ ?

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Answer 1 · 2018-06-02T15:08:10

$(4-m)(4m+3n)$

notice:

$4mcolor(red)((4 - m )) + 3ncolor(red)(( 4 - m )$

$color(red)( (4-m) )$ is common in each, this whole term can be factored out

$=> color(red)( (4-m) ) [ 4m + 3n ]$

$color(blue)( = ( 4-m )( 4m + 3n)$

This is the most simplified factorisation

How do you factor 4m(4 - m) + 3n(4 - m)4m(4 - m) + 3n(4 - m)?