How do you factor $4 p^{2} q + p q^{2} + 4 p^{3}$ $4p^2q+pq^2+4p^3$ by grouping?

Question

How do you factor $4 p^{2} q + p q^{2} + 4 p^{3}$ $4p^2q+pq^2+4p^3$ by grouping?

1 Answer

Impact of this question

1369 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-06-21T17:45:44

$4 p^{2} q + p q^{2} + 4 p^{3} = p (q + 2 p) (q + 2 p)$ $4p^2q+pq^2+4p^3=p(q+2p)(q+2p)$

Explanation:

Separate out the common factor $p$ $p$ , rearrange into descending powers of $q$ $q$ then recognise the perfect square trinomial:

$4 p^{2} q + p q^{2} + 4 p^{3}$ $4p^2q+pq^2+4p^3$

$= p (4 p q + q^{2} + 4 p^{2})$ $=p(4pq+q^2+4p^2)$

$= p (q^{2} + 4 p q + 4 p^{2})$ $=p(q^2+4pq+4p^2)$

$= p (q + 2 p) (q + 2 p)$ $=p(q+2p)(q+2p)$

Science

Math

Humanities

... and beyond

How do you factor $4 p^{2} q + p q^{2} + 4 p^{3}$ $4p^2q+pq^2+4p^3$ by grouping?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you factor 4p2q+pq2+4p34p^2q+pq^2+4p^3 by grouping?

1 Answer

Explanation:

Related questions

Impact of this question

How do you factor $4 p^{2} q + p q^{2} + 4 p^{3}$ $4p^2q+pq^2+4p^3$ by grouping?