How do you factor #4p^2q+pq^2+4p^3# by grouping?
1 Answer
Jun 21, 2016
#4p^2q+pq^2+4p^3=p(q+2p)(q+2p)#
Explanation:
Separate out the common factor
#4p^2q+pq^2+4p^3#
#=p(4pq+q^2+4p^2)#
#=p(q^2+4pq+4p^2)#
#=p(q+2p)(q+2p)#
