How do you factor #4r^2-13rt+9t^2#?

1 Answer
May 6, 2016

Answer:

#4r^2-13rt+9t^2=(4r-9t)(r-t)#

Explanation:

There are several ways to see this, but since the coefficients add up to #0# we find that #(r-t)# is a factor, which we can show by grouping:

#4r^2-13rt+9t^2#

#=4r^2-4rt-9rt+9t^2#

#=(4r^2-4rt)-(9rt-9t^2)#

#=4r(r-t)-9t(r-t)#

#=(4r-9t)(r-t)#