How do you factor $4 r^{2} - 13 r t + 9 t^{2}$ $4r^2-13rt+9t^2$ ?

Question

How do you factor $4 r^{2} - 13 r t + 9 t^{2}$ $4r^2-13rt+9t^2$ ?

1 Answer

Impact of this question

1150 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-05-06T19:33:07

$4 r^{2} - 13 r t + 9 t^{2} = (4 r - 9 t) (r - t)$ $4r^2-13rt+9t^2=(4r-9t)(r-t)$

Explanation:

There are several ways to see this, but since the coefficients add up to $0$ $0$ we find that $(r - t)$ $(r-t)$ is a factor, which we can show by grouping:

$4 r^{2} - 13 r t + 9 t^{2}$ $4r^2-13rt+9t^2$

$= 4 r^{2} - 4 r t - 9 r t + 9 t^{2}$ $=4r^2-4rt-9rt+9t^2$

$= (4 r^{2} - 4 r t) - (9 r t - 9 t^{2})$ $=(4r^2-4rt)-(9rt-9t^2)$

$= 4 r (r - t) - 9 t (r - t)$ $=4r(r-t)-9t(r-t)$

$= (4 r - 9 t) (r - t)$ $=(4r-9t)(r-t)$

Science

Math

Humanities

... and beyond

How do you factor $4 r^{2} - 13 r t + 9 t^{2}$ $4r^2-13rt+9t^2$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you factor 4r^2-13rt+9t^24r2−13rt+9t24r^2-13rt+9t^2?

1 Answer

Explanation:

Related questions

Impact of this question

How do you factor $4 r^{2} - 13 r t + 9 t^{2}$ $4r^2-13rt+9t^2$ ?