# How do you factor 4x^2 + 12x - 64?

Jul 17, 2016

$f \left(x\right) = 4 \left({x}^{2} + 3 x - 16\right)$

#### Explanation:

$f \left(x\right) = 4 y = 4 \left({x}^{2} + 3 x - 16\right)$
Factor y.
$D = {b}^{2} - 4 a c = 9 + 64 = 73$
Since D is not a perfect square, there for, y can't be factored.
$f \left(x\right) = 4 \left({x}^{2} + 3 x - 16\right)$