How do you factor #4x^2-12x+9#?
Use the rainbow method.
Multiply the two outer coefficients.
Find two numbers, that when multiplied equal 36, and when added equal -12.
-6 and -6.
Rewrite the equation with the x value replaced by the two new values.
Seperate the equation into two parts.
Find the GCF of the two parts.
Take the GCF as your first factor, and the two remaining values as the second.
2x-3 and 2x-3
First, factor x^2
Then, identify the y element in the form
Last, factor the perfect square trinomial