How do you factor 4x^2-16x+15?

1 Answer
Jun 2, 2016

4x^2-16x+15=(2x-3)(2x-5)

Explanation:

To factorize ax^2+bx+c, one should split middle term in two parts, so that their product is ac and sum is b.

Hence in 4x^2-16x+15, while the product should be 4xx15=60, sum should be -16. It is apparent that these are -6 and -10.

Hence 4x^2-16x+15

= 4x^2-10x-6x+15

= 2x(2x-5)-3(2x-5)

= (2x-3)(2x-5)