How do you factor #4x^2-36y^2 #?

1 Answer
Jan 8, 2016

Answer:

(2x - 6y )(2x + 6y )

Explanation:

# a^2 - b^2 #

is a difference of two squares since the values on either side of the difference (- ) are perfect squares. the factor of

# a^2 - b^2 = (a - b)(a + b )#

in the question given then a = 2x and b = 6y

# rArr 4x^2- 36y^2 = (2x - 6y )(2x + 6y ) #