# How do you factor 4x^2+38x+34=0 ?

Dec 17, 2015

Factor $f \left(x\right) = 4 {x}^{2} + 38 x + 34 = 0$
$f \left(x\right) = 2 y = 2 \left(2 {x}^{2} + 19 x + 17\right) = 0. F a c \to r y .$
Since (a - b + c = 0) use the shortcut. The 2 real roots are: -1 and $- \frac{c}{a} = - \frac{17}{2}$. The 2 factors are: (x + 1) and (x + 17/2)
Factored form $f \left(x\right) = 2 \left(x + 1\right) \left(2 x + 17\right)$