How do you factor #4x^2+38x+34=0 #?

1 Answer
Dec 17, 2015

Answer:

Factor #f(x) = 4x^2 + 38x + 34 = 0#

Ans: f(x) = 2(x + 1)(2x + 17)

Explanation:

#f(x) = 2y = 2(2x^2 + 19x + 17) = 0. Factor y.#
Since (a - b + c = 0) use the shortcut. The 2 real roots are: -1 and #-c/a = -17/2#. The 2 factors are: (x + 1) and (x + 17/2)
Factored form #f(x) = 2(x + 1)(2x + 17)#