How do you factor $4x^2 -9$ ?

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Answer 1 · 2015-05-31T18:58:58

This is a difference of squares:

$4x^2-9 = (2x)^2 - 3^2$

So you can use the difference of squares identity

$a^2 - b^2 = (a-b)(a+b)$

to find...

$(2x)^2 - 3^2 = (2x-3)(2x+3)$

How do you factor 4x^2 -94x^2 -9?