Question

How do you factor `(4x-3)^2 - (x+1)^2`?

Answer 1

(3x-4)(5x-2)

Use the identity `a^2-b^2`= (a-b)(a+b). Factors would be (4x-3-x-1)(4x-3+x+1)

(3x-4)(5x-2)