How do you factor #4x^3 - 32= 0#?

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Answer 1 · 2018-05-03T03:56:45

#x = 2#

#4x^3 - 32 = 0#

Factor out the #4#:
#4(x^3 - 8) = 0#

Divide both sides by #color(blue)4#:
#(4(x^3 - 8))/color(blue)4 = 0/color(blue)4#

#x^3 - 8 = 0#

Add #color(blue)8# to both sides of the equation:
#x^3 - 8 quadcolor(blue)(+quad8) = 0 quadcolor(blue)(+quad8)#

#x^3 = 8#

Take the cube root of both sides:
#root(3)(x^3) = root(3)(8)#

#x = 2#

Hope this helps!