# How do you factor 4x^3 - 32= 0?

May 3, 2018

$x = 2$

#### Explanation:

$4 {x}^{3} - 32 = 0$

Factor out the $4$:
$4 \left({x}^{3} - 8\right) = 0$

Divide both sides by $\textcolor{b l u e}{4}$:
$\frac{4 \left({x}^{3} - 8\right)}{\textcolor{b l u e}{4}} = \frac{0}{\textcolor{b l u e}{4}}$

${x}^{3} - 8 = 0$

Add $\textcolor{b l u e}{8}$ to both sides of the equation:
${x}^{3} - 8 \quad \textcolor{b l u e}{+ \quad 8} = 0 \quad \textcolor{b l u e}{+ \quad 8}$

${x}^{3} = 8$

Take the cube root of both sides:
$\sqrt[3]{{x}^{3}} = \sqrt[3]{8}$

$x = 2$

Hope this helps!