How do you factor $4 x^{3} - x^{2} + 4 x - 1$ $4x^3 - x^2 + 4x -1$ ?

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How do you factor $4 x^{3} - x^{2} + 4 x - 1$ $4x^3 - x^2 + 4x -1$ ?

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Answer 1 · 2015-05-28T15:12:30

We can make groups of two to factorise this expression:
$(4 x^{3} + 4 x) - (x^{2} + 1)$ $(4x^3 +4x) - (x^2+1)$
$4 x$ $4x$ is common to both the terms in the first group.
We can write the expression as :
$4 x (x^{2} + 1) - 1 (x^{2} + 1)$ $4x(x^2 +1) - 1(x^2+1)$
$= (4 x - 1) (x^{2} + 1)$ $=color(blue)((4x-1)(x^2+1)$

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How do you factor $4 x^{3} - x^{2} + 4 x - 1$ $4x^3 - x^2 + 4x -1$ ?

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How do you factor $4 x^{3} - x^{2} + 4 x - 1$ $4x^3 - x^2 + 4x -1$ ?